물리:짚고_넘어가야_할_점

Differences

This shows you the differences between two versions of the page.

Link to this comparison view

Next revisionBoth sides next revision
물리:짚고_넘어가야_할_점 [2022/12/02 14:18] – created jiwon물리:짚고_넘어가야_할_점 [2022/12/02 14:54] jiwon
Line 98: Line 98:
  \right)  \right)
 $$ $$
-복제 대칭해의 경우에 얻었던 $n(n-1)2$의 중복도를 가지는 replicon mode를 똑같이 얻어내었다. +복제 대칭해의 경우에 얻었던 $n(n-1)2$의 중복도를 가지는 replicon mode를 똑같이 얻어내었다. 만약 $n=4$, $m_1=1$이라면 
 +$$ 
 +\mathbf G= 
 +\left( 
 +\begin{array}{cccccccccc} 
 + A & B_0 & B_0 & B_0 & C_0 & C_0 & C_0 & D_{02} & D_{02} & D_{02} \\ 
 +  B_0 & A & B_0 & B_0 & C_0 & D_{02} & D_{02} & C_0 & C_0 & D_{02} \\ 
 + B_0 & B_0 & A & B_0 & D_{02} & C_0 & D_{02} & C_0 & D_{02} & C_0 \\ 
 +   B_0 & B_0 & B_0 & A & D_{02} & D_{02} & C_0 & D_{02} & C_0 & C_0 \\ 
 + C_0 & C_0 & D_{02} & D_{02} & P_0 & Q_{00} & Q_{00} & Q_{00} & \ 
 + Q_{00} & R_{1:1:1:1} \\ 
 +   C_0 & D_{02} & C_0 & D_{02} & Q_{00} & P_0 & Q_{00} & Q_{00} & \ 
 + R_{1:1:1:1} & Q_{00} \\ 
 + C_0 & D_{02} & D_{02} & C_0 & Q_{00} & Q_{00} & P_0 & R_{1:1:1:1} & \ 
 + Q_{00} & Q_{00} \\ 
 +   D_{02} & C_0 & C_0 & D_{02} & Q_{00} & Q_{00} & R_{1:1:1:1} & P_0 & \ 
 + Q_{00} & Q_{00} \\ 
 + D_{02} & C_0 & D_{02} & C_0 & Q_{00} & R_{1:1:1:1} & Q_{00} & Q_{00} \ 
 + & P_0 & Q_{00} \\ 
 +   D_{02} & D_{02} & C_0 & C_0 & R_{1:1:1:1} & Q_{00} & Q_{00} & Q_{00} \ 
 + & Q_{00} & P_0 \\ 
 + \end{array} 
 + \right) 
 +$$ 
 +고윳값들은 
 +$$ 
 +\left( 
 +\begin{array}{c} 
 + P_0-2 Q_{00}+R_{1:1:1:1} \\ 
 +  P_0-2 Q_{00}+R_{1:1:1:1} \\ 
 + \frac{1}{2} \left(-\sqrt{(A+3 B_0+P_0+4 Q_{00}+R_{1:1:1:1})^2-4 (A+3 \ 
 + B_0) (P_0+4 Q_{00}+R_{1:1:1:1})+24 C_0^2+48 C_0 D_{02}+24 \ 
 + D_{02}^2}+A+3 B_0+P_0+4 Q_{00}+R_{1:1:1:1}\right) \\ 
 +   \frac{1}{2} \left(\sqrt{(A+3 B_0+P_0+4 Q_{00}+R_{1:1:1:1})^2-4 (A+3 \ 
 + B_0) (P_0+4 Q_{00}+R_{1:1:1:1})+24 C_0^2+48 C_0 D_{02}+24 \ 
 + D_{02}^2}+A+3 B_0+P_0+4 Q_{00}+R_{1:1:1:1}\right) \\ 
 + \frac{1}{2} \left(-\sqrt{(A-B_0+P_0-R_{1:1:1:1})^2-4 (A-B_0) \ 
 + (P_0-R_{1:1:1:1})+8 C_0^2-16 C_0 D_{02}+8 \ 
 + D_{02}^2}+A-B_0+P_0-R_{1:1:1:1}\right) \\ 
 +   \frac{1}{2} \left(-\sqrt{(A-B_0+P_0-R_{1:1:1:1})^2-4 (A-B_0) \ 
 + (P_0-R_{1:1:1:1})+8 C_0^2-16 C_0 D_{02}+8 \ 
 + D_{02}^2}+A-B_0+P_0-R_{1:1:1:1}\right) \\ 
 + \frac{1}{2} \left(-\sqrt{(A-B_0+P_0-R_{1:1:1:1})^2-4 (A-B_0) \ 
 + (P_0-R_{1:1:1:1})+8 C_0^2-16 C_0 D_{02}+8 \ 
 + D_{02}^2}+A-B_0+P_0-R_{1:1:1:1}\right) \\ 
 +   \frac{1}{2} \left(\sqrt{(A-B_0+P_0-R_{1:1:1:1})^2-4 (A-B_0) \ 
 + (P_0-R_{1:1:1:1})+8 C_0^2-16 C_0 D_{02}+8 \ 
 + D_{02}^2}+A-B_0+P_0-R_{1:1:1:1}\right) \\ 
 + \frac{1}{2} \left(\sqrt{(A-B_0+P_0-R_{1:1:1:1})^2-4 (A-B_0) \ 
 + (P_0-R_{1:1:1:1})+8 C_0^2-16 C_0 D_{02}+8 \ 
 + D_{02}^2}+A-B_0+P_0-R_{1:1:1:1}\right) \\ 
 +   \frac{1}{2} \left(\sqrt{(A-B_0+P_0-R_{1:1:1:1})^2-4 (A-B_0) \ 
 + (P_0-R_{1:1:1:1})+8 C_0^2-16 C_0 D_{02}+8 \ 
 + D_{02}^2}+A-B_0+P_0-R_{1:1:1:1}\right) \\ 
 + \end{array} 
 + \right) 
 +$$ 
 +와 같다.
  
  • 물리/짚고_넘어가야_할_점.txt
  • Last modified: 2023/09/05 15:46
  • by 127.0.0.1