물리:bbgky_계층

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물리:bbgky_계층 [2022/04/19 13:37] – [푸아송 괄호 계산] jiwon물리:bbgky_계층 [2022/04/21 17:24] – [푸아송 괄호 계산] jiwon
Line 31: Line 31:
 $$H' = \sum_{n=1}^s\sum_{i=s+1}^NV(\vec q_n-\vec q_j)$$ $$H' = \sum_{n=1}^s\sum_{i=s+1}^NV(\vec q_n-\vec q_j)$$
  
-여기에 리우빌 정리를 적용하면, $\rho_s$의 시간변화는 +여기에 [[물리:리우빌 정리]]를 적용하면, $\rho_s$의 시간변화는 
  
 $$\frac{\partial\rho_s}{\partial t} = \int\prod_{i=s+1}^Nd^3p_id^3q_i\frac{\partial\rho}{\partial t} = -\int\prod_{i=s+1}^Nd^3p_id^3q_i \{\rho,H_s+H_{N-s}+H'\}$$ $$\frac{\partial\rho_s}{\partial t} = \int\prod_{i=s+1}^Nd^3p_id^3q_i\frac{\partial\rho}{\partial t} = -\int\prod_{i=s+1}^Nd^3p_id^3q_i \{\rho,H_s+H_{N-s}+H'\}$$
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  \int \prod_{i=s+1}^N d^3p_id^3q_i\{\rho,H_{N-s}\} &= \int \prod_{i=s+1}^N d^3p_id^3q_i\sum_{j=1}^N\left[\frac{\partial\rho}{\partial\vec q_j}\cdot\frac{\partial H_{N-s}}{\partial\vec p_j}-\frac{\partial\rho}{\partial\vec p_j}\cdot\frac{\partial H_{N-s}}{\partial\vec q_j}\right]  \int \prod_{i=s+1}^N d^3p_id^3q_i\{\rho,H_{N-s}\} &= \int \prod_{i=s+1}^N d^3p_id^3q_i\sum_{j=1}^N\left[\frac{\partial\rho}{\partial\vec q_j}\cdot\frac{\partial H_{N-s}}{\partial\vec p_j}-\frac{\partial\rho}{\partial\vec p_j}\cdot\frac{\partial H_{N-s}}{\partial\vec q_j}\right]
 \end{align*} \end{align*}
-이고, $s+1\le j\le N$인 $j$에 대해+이고, 각각의 $j$항을 따로 계산할 수 있다.
 \begin{align*} \begin{align*}
- \frac{\partial H_{N-s}}{\partial\vec p_j} &\frac{\vec p_j}{m}\\ + &\int d^3p_jd^3q_j\left[\frac{\partial\rho}{\partial\vec q_j}\cdot\frac{\partial H_{N-s}}{\partial\vec p_j}-\frac{\partial\rho}{\partial\vec p_j}\cdot\frac{\partial H_{N-s}}{\partial\vec q_j}\right]\\ 
- \frac{\partial H_{N-s}}{\partial\vec q_j} &= \frac{\partial U(\vec q_j)}{\partial\vec q_j} \frac12\sum_{k=s+1}\frac{V(\vec q_j-\vec q_k)}{\partial\vec q_j}+ =&\int d^3p_j\left[\rho\frac{\partial H_{N-s}}{\partial\vec p_j}\right]_{\vec q_j\text{ at }\infty}-\int d^3q_j\left[\rho\frac{\partial H_{N-s}}{\partial\vec q_j}\right]_{\vec p_j\textat }\infty}+\int d^3p_jd^3q_j \rho\left[-\frac{\partial^2H_{N-s}}{\partial\vec p_j\partial\vec q_j}+\frac{\partial^2H_{N-s}}{\partial\vec q_j\partial\vec p_j}\right]\\ 
 + =&0
 \end{align*} \end{align*}
-로 +는 우리가 고려하고자 하는 $s$개의 입자를 제외한 나머지들 끼리의 운동은 $\rho_s$에 아무 영향을 끼치지 않음을 의미한다. 
 + 
 +===세 번째 항=== 
 +마찬가지로 푸아송 괄호를 풀어서 적어보면
 \begin{align*} \begin{align*}
- &\int \prod_{i=s+1}^N d^3p_id^3q_i\sum_{j=s+1}^N\left[\frac{\partial\rho}{\partial\vec q_j}\cdot\frac{\vec p_j}{m}-\frac{\partial\rho}{\partial\vec p_j}\cdot\left(\frac{\partial U(\vec q_j)}{\partial\vec q_j\frac12\sum_{k=s+1}\frac{V(\vec q_j-\vec q_k)}{\partial\vec q_j}\right)\right]+ \int \prod_{i=s+1}^N d^3p_id^3q_i\sum_{j=1}^N\left[\frac{\partial\rho}{\partial\vec q_j}\cdot\frac{\partial H'}{\partial\vec p_j}-\frac{\partial\rho}{\partial\vec p_j}\cdot\frac{\partial H'}{\partial\vec q_j}\right]
 \end{align*} \end{align*}
-이다. 위의 적분은 사실 $0$이 되는데 $j$하나를 골라서 적분해보면 +이다. $\partial H'/\partial\vec q_j=0$이 되고, $j\le s$일 때 
 +\begin{align*} 
 + \frac{\partial H'}{\partial\vec q_j} = \frac{\partial}{\partial\vec q_j}\left(\sum_{n=1}^s\sum_{i=s+1}^NV(\vec q_n-\vec q_i)\right) = \sum_{i=s+1}^NV(\vec q_j-\vec q_i) 
 +\end{align*} 
 +$s+1\le j\le N$일 때는 
 +\begin{align*} 
 + \frac{\partial H'}{\partial\vec q_j} = \frac{\partial}{\partial\vec q_j}\left(\sum_{n=1}^s\sum_{i=s+1}^NV(\vec q_n-\vec q_i)\right) = \sum_{n=1}^sV(\vec q_n-\vec q_j) 
 +\end{align*} 
 +이므로, 이를 모두 모아서 적보면 
 +\begin{align*} 
 + &\int \prod_{i=s+1}^N d^3p_id^3q_i\sum_{j=1}^N\left[\frac{\partial\rho}{\partial\vec q_j}\cdot\frac{\partial H'}{\partial\vec p_j}-\frac{\partial\rho}{\partial\vec p_j}\cdot\frac{\partial H'}{\partial\vec q_j}\right]\\ 
 + =&\int \prod_{i=s+1}^N d^3p_id^3q_i\left[\sum_{n=1}^s\frac{\partial\rho}{\partial\vec p_n}\cdot\sum_{j=s+1}^N\frac{\partial V(\vec q_n-\vec q_j)}{\partial\vec q_n} + \sum_{j=s+1}^N\frac{\partial\rho}{\partial\vec p_j}\cdot\sum_{n=1}^s\frac{\partial V(\vec q_j-\vec q_n)}{\partial\vec  q_j}\right] 
 +\end{align*} 
 +이 된다.
  • 물리/bbgky_계층.txt
  • Last modified: 2023/09/05 15:46
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