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물리:결맞는_상태_coherent_state [2024/12/24 18:48] – minwoo | 물리:결맞는_상태_coherent_state [2024/12/25 08:50] (current) – minwoo | ||
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- | & \sigma_x \sigma_p =\hbar^2 \left(n+\frac{1}{2}\right)^2 \ge \left( \frac{\hbar}{2} \right)^2 \quad \left(\because \ \sigma_A = \langle A^2 \rangle - \langle A \rangle ^2 \right) | + | & \sigma_x^2 \sigma_p^2 =\hbar^2 \left(n+\frac{1}{2}\right)^2 \ge \left( \frac{\hbar}{2} \right)^2 \quad \left(\because \ \sigma_A^2 = \langle A^2 \rangle - \langle A \rangle ^2 \right) |
\end{align} | \end{align} | ||
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{{: | {{: | ||
- | 위의 폭은 $ \sigma_x \sigma_p =\hbar^2 \left(n+\frac{1}{2}\right)^2 \ge \left( \frac{\hbar}{2} \right)^2 $의 불확정성에 의한 것이다. | + | 위의 폭은 $ \sigma_x^2 \sigma_p^2 =\hbar^2 \left(n+\frac{1}{2}\right)^2 \ge \left( \frac{\hbar}{2} \right)^2 $의 불확정성에 의한 것이다. |
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- | & \sigma_x \sigma_p =(\frac{\hbar}{2m\omega})(\frac{\hbar m\omega}{2})=\left(\frac{\hbar}{2}\right)^2 | + | & \sigma_x^2 \sigma_p^2 =(\frac{\hbar}{2m\omega})(\frac{\hbar m\omega}{2})=\left(\frac{\hbar}{2}\right)^2 |
\end{align} | \end{align} | ||