Differences
This shows you the differences between two versions of the page.
| Both sides previous revision Previous revision | |||
| 물리:결맞는_상태_coherent_state [2024/12/24 18:48] – minwoo | 물리:결맞는_상태_coherent_state [2024/12/25 08:50] (current) – minwoo | ||
|---|---|---|---|
| Line 247: | Line 247: | ||
| \\ | \\ | ||
| - | & \sigma_x \sigma_p =\hbar^2 \left(n+\frac{1}{2}\right)^2 \ge \left( \frac{\hbar}{2} \right)^2 \quad \left(\because \ \sigma_A = \langle A^2 \rangle - \langle A \rangle ^2 \right) | + | & \sigma_x^2 \sigma_p^2 =\hbar^2 \left(n+\frac{1}{2}\right)^2 \ge \left( \frac{\hbar}{2} \right)^2 \quad \left(\because \ \sigma_A^2 = \langle A^2 \rangle - \langle A \rangle ^2 \right) |
| \end{align} | \end{align} | ||
| Line 266: | Line 266: | ||
| {{: | {{: | ||
| - | 위의 폭은 $ \sigma_x \sigma_p =\hbar^2 \left(n+\frac{1}{2}\right)^2 \ge \left( \frac{\hbar}{2} \right)^2 $의 불확정성에 의한 것이다. | + | 위의 폭은 $ \sigma_x^2 \sigma_p^2 =\hbar^2 \left(n+\frac{1}{2}\right)^2 \ge \left( \frac{\hbar}{2} \right)^2 $의 불확정성에 의한 것이다. |
| ==== ' | ==== ' | ||
| Line 305: | Line 305: | ||
| \\ | \\ | ||
| - | & \sigma_x \sigma_p =(\frac{\hbar}{2m\omega})(\frac{\hbar m\omega}{2})=\left(\frac{\hbar}{2}\right)^2 | + | & \sigma_x^2 \sigma_p^2 =(\frac{\hbar}{2m\omega})(\frac{\hbar m\omega}{2})=\left(\frac{\hbar}{2}\right)^2 |
| \end{align} | \end{align} | ||